In a quadrilateral ABCD, the angles A, B, C and D are in ratio 1:2:3:4. Find the measure of each angle of the quadrilateral.
Answer:
∠A = 36°, ∠B = 72°, ∠C = 108°, ∠D = 144°
- Let's assume x is the common factor of the angles of the quadrilateral.
According to the question, the angles A, B, C and D are in ratio 1:2:3:4.
Therefore,
∠A = 1x,
∠B = 2x,
∠C = 3x and
∠D = 4x. - We know that the sum of all interior angles of a quadrilateral is equal to 360°.
Therefore, ∠A + ∠B + ∠C + ∠D = 360°
⇒ 1x + 2x + 3x + 4x = 360°
⇒ 10x = 360
⇒ x =360 10
⇒ x = 36 - Hence, ∠A = 1x = 1 × 36 = 36°,
∠B = 2x = 2 × 36 = 72°,
∠C = 3x = 3 ×36 = 108° and
∠D = 4x = 4 × 36 = 144°.